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Hampel Filter

滤波器算法

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def hampel(vals_orig, k=7, t0=3):
'''
vals: pandas series of values from which to remove outliers
k: size of window (including the sample; 7 is equal to 3 on either side of value)
'''

#Make copy so original not edited
vals = vals_orig.copy()

#Hampel Filter
L = 1.4826
rolling_median = vals.rolling(window=k, center=True).median()
MAD = lambda x: np.median(np.abs(x - np.median(x)))
rolling_MAD = vals.rolling(window=k, center=True).apply(MAD)
threshold = t0 * L * rolling_MAD
difference = np.abs(vals - rolling_median)

'''
Perhaps a condition should be added here in the case that the threshold value
is 0.0; maybe do not mark as outlier. MAD may be 0.0 without the original values
being equal. See differences between MAD vs SDV.
'''

outlier_idx = difference > threshold
vals[outlier_idx] = rolling_median[outlier_idx]
return(vals)